Thursday, August 6, 2026

Gas Laws and Partial Pressure UPCAT Reviewer: Lesson and Practice

TEACHER ABI UPCAT SCIENCE

Gas Laws and Partial Pressure

Identify what stays constant, use absolute temperature, and connect gas equations to particle motion and real situations.

5-10 minute lesson27 original questionsAdaptive practiceSaves progress
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Gas Laws and Partial Pressure

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A gas-law equation is useful only after you identify what is held constant

Boyle: P₁V₁ = P₂V₂   (constant T and n)Charles: V₁/T₁ = V₂/T₂   (constant P and n)Gay-Lussac: P₁/T₁ = P₂/T₂   (constant V and n)Combined: P₁V₁/T₁ = P₂V₂/T₂Ideal gas: PV = nRT

Temperature must be in kelvins. Gas laws describe macroscopic patterns, while the particle model explains them: pressure comes from wall collisions, temperature reflects average kinetic energy, and volume determines the space available to particles.

For nonreacting gas mixtures, Dalton’s law gives Ptotal = P₁ + P₂ + …, while Pi = XiPtotal and Xi = ni/ntotal.

Name the constants first

A rigid tank fixes volume; a flexible balloon often stays near external pressure; an “isothermal” change fixes temperature; a sealed container fixes amount of gas.

Never use Celsius in a proportion

Convert using K = °C + 273. A change from 20°C to 40°C is 293 K to 313 K—not a doubling of temperature.

DO IT FAST

Use arrows before algebra to catch impossible answers

Problem: A gas is compressed at constant temperature.

Identify the law: T and n are constant → Boyle’s law.

Predict first: Volume goes down, so pressure must go up.

Calculate: If volume becomes one-fourth as large, pressure becomes four times as large.

Check: Reject any answer showing both pressure and volume decreasing under the stated conditions.

Why it works

A qualitative prediction exposes unit, inversion, and calculator errors before they become final answers.

WORKED EXAMPLES

Five forms you should recognize

1. Boyle’s law

Problem: A gas occupies 4.0 L at 100 kPa and is compressed to 2.0 L at constant temperature.

P₂ = 100(4.0)/2.0 = 200 kPa

Halving volume doubles pressure.

2. Charles’s law

Problem: A 3.0 L balloon warms from 300 K to 400 K at constant pressure.

V₂ = 3.0(400/300) = 4.0 L
3. Rigid tank

Problem: A sealed rigid tank warms from 300 K to 450 K while starting at 120 kPa.

P₂ = 120(450/300) = 180 kPa
4. Partial pressure

Problem: Gas A has mole fraction 0.30 at a total pressure of 500 kPa.

P_A = 0.30(500) = 150 kPa
5. Collected over water

Problem: Total pressure is 101 kPa and water-vapor pressure is 3 kPa.

P_dry gas = 101 − 3 = 98 kPa
COMMON TRAPS

Check before you commit

  • Using Celsius in gas-law ratios
  • Choosing a law before identifying constants
  • Forgetting the inverse pressure–volume relationship
  • Treating partial pressures as averages instead of contributions
  • Assuming heating always raises pressure even when volume can change
  • Using the pressure of wet gas as though no water vapor were present
FIVE-FORM SKILL CHECK

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Foundations

Build the core procedure with immediate explanations.

Core Practice

Use mixed forms with less scaffolding.

UPCAT-Style Transfer

Apply the competency in unfamiliar representations.

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QUICK ANSWERS

Gas Laws and Partial Pressure FAQ

Why does pressure rise in a heated rigid tank?

Particles move faster and strike the fixed walls more often and with greater momentum change.

Are real gases always ideal?

No. Ideal behavior is an approximation that works best at relatively low pressure and high temperature.

Why does a balloon expand at high altitude?

Lower external pressure allows the trapped gas to occupy a larger volume.

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