Thursday, August 20, 2026

Electrochemistry UPCAT Reviewer: Lesson and Practice

TEACHER ABI UPCAT MATHEMATICS

Electrochemistry

Track electron transfer, identify electrodes and agents, calculate cell potential, and interpret galvanic cells, electrolysis, plating, and corrosion.

5-10 minute lesson27 original questionsAdaptive practiceSaves progress
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Electrochemistry

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Electrons leave the anode and arrive at the cathode

Oxidation is loss of electrons; reduction is gain of electrons.

AN OX: oxidation at the anodeRED CAT: reduction at the cathodeelectron flow: anode → cathode

These electrode reactions are always true. What changes between galvanic and electrolytic cells is the electrode sign and the direction of energy conversion.

Galvanic cell

A spontaneous redox reaction produces electrical energy; anode is negative and cathode is positive.

Electrolytic cell

Electrical energy drives a nonspontaneous change; anode is positive and cathode is negative.

Salt bridge carries ions

Electrons travel through the wire; ions migrate through the electrolyte and bridge.

Oxidizing agent is reduced

It accepts electrons from the species it oxidizes.

Cell potential

Using reduction potentials: E°cell = E°cathode−E°anode.

DO IT FAST

Use AN OX → wire → RED CAT

Write the oxidation half-reaction at the left and the reduction half-reaction at the right:

ANODE: atoms lose e⁻ → e⁻ flow → CATHODE: ions gain e⁻

Then check mass: a reactive metal anode often dissolves, while metal ions can plate onto the cathode.

Why it works

This single map prevents the most common mix-ups involving electrode names, electron direction, and which species gains or loses mass.

WORKED EXAMPLES

Five forms you should recognize

1. Zinc-copper cell

Problem: In Zn|Zn²⁺ || Cu²⁺|Cu, identify oxidation, reduction, and electron direction.

anode: Zn→Zn²⁺+2e⁻cathode: Cu²⁺+2e⁻→Cu

Electrons travel from the zinc electrode to the copper electrode.

2. Cell potential

Problem: E°red(Cu²⁺/Cu) = +0.34 V and E°red(Zn²⁺/Zn) = −0.76 V.

E°cell = 0.34−(−0.76) = +1.10 V

The positive standard potential supports a spontaneous galvanic reaction as written.

3. Oxidation number

Problem: Find Mn in KMnO₄.

(+1) + Mn + 4(−2) = 0Mn = +7
4. Electroplating

Problem: A metal coating is deposited on an object.

The object is the cathode because metal ions gain electrons there and become solid metal.

5. Sacrificial protection

Problem: Magnesium is attached to an iron pipeline.

Magnesium oxidizes more readily and supplies electrons, so it corrodes in place of the iron.

COMMON TRAPS

Check before you commit

  • Sending electrons through the salt bridge
  • Saying reduction happens at the anode
  • Changing the anodecathode reaction rule between cell types
  • Calling the oxidized species the oxidizing agent
  • Adding reduction potentials without reversing the anode term
  • Assuming a positive ion plates at the anode
FIVE-FORM SKILL CHECK

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CHOOSE YOUR PRACTICE

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Foundations

Build the core procedure with immediate explanations.

Core Practice

Use mixed forms with less scaffolding.

UPCAT-Style Transfer

Apply the competency in unfamiliar representations.

FRESH MASTERY CHECK

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QUICK ANSWERS

Electrochemistry FAQ

Are anode and cathode signs always the same?

No. Their reaction roles stay fixed, but their signs differ between galvanic and electrolytic cells.

What moves through the salt bridge?

Ions, not electrons, move to maintain electrical neutrality.

Why does a positive E°cell matter?

Under standard conditions it indicates that the redox reaction is thermodynamically favored in the written direction.

RELATED COMPETENCIES

Continue your mathematics review.

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