Thursday, August 6, 2026

Electricity and Electric Circuits UPCAT Reviewer: Lesson and Practice

TEACHER ABI UPCAT SCIENCE

Electricity and Electric Circuits

Read circuit relationships, combine resistors, interpret electrical data, and connect power calculations to real devices and safety.

5-10 minute lesson27 original questionsAdaptive practiceSaves progress
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Electricity and Electric Circuits

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QUICK REVIEW

Start with the circuit path, then apply voltage, current, and resistance relationships

Ohm’s law: V = IRpower: P = VI = I²R = V²/Relectrical energy: E = Pt

In a series circuit, there is one path: current is the same through every component, resistances add, and voltage is divided. In a parallel circuit, branches share the same two nodes: voltage is the same across each branch, branch currents add, and equivalent resistance is smaller than the smallest branch resistance.

An ammeter has very low resistance and is placed in series. A voltmeter has very high resistance and is placed in parallel across the component being measured.

Track what stays the same

Series → same current. Parallel → same voltage. Write this before calculating.

Equivalent resistance predicts total current

Adding resistance in series raises equivalent resistance. Adding another parallel path lowers equivalent resistance and can increase total source current.

DO IT FAST

Reduce the circuit from the inside out

Series group: Add the resistances.

Parallel pair: Use 1/Req = 1/R₁ + 1/R₂, or Req = R₁R₂/(R₁ + R₂).

Then: Find total current from I = V/Req. Expand the circuit again to find branch voltages and currents.

Final check: Parallel branch currents must add to the total current.

Why it works

Trying to solve every branch simultaneously causes avoidable errors. Reduction converts a complicated network into a single source-and-resistance problem before working backward.

WORKED EXAMPLES

Five forms you should recognize

1. Simple Ohm’s law

Problem: A 12 V source is connected across 4 Ω.

I = 12/4 = 3 A
2. Series circuit

Problem: Resistors of 2 Ω and 4 Ω are in series across 12 V.

Req = 6 Ω; I = 12/6 = 2 A

The voltage drops are 4 V and 8 V.

3. Parallel circuit

Problem: Resistors of 6 Ω and 3 Ω are in parallel.

Req = (6×3)/(6+3) = 2 Ω
4. Electrical power

Problem: A device uses 2 A at 12 V.

P = 12(2) = 24 W
5. Energy use

Problem: A 1 kW appliance runs for 0.5 h.

E = 1(0.5) = 0.5 kWh
COMMON TRAPS

Check before you commit

  • Adding parallel resistances directly
  • Dividing current equally between unequal parallel branches
  • Putting an ammeter across a battery
  • Putting a voltmeter in series
  • Confusing power in watts with energy in kilowatt-hours
  • Forgetting that total current increases when more parallel loads are added
FIVE-FORM SKILL CHECK

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CHOOSE YOUR PRACTICE

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Foundations

Build the core procedure with immediate explanations.

Core Practice

Use mixed forms with less scaffolding.

UPCAT-Style Transfer

Apply the competency in unfamiliar representations.

FRESH MASTERY CHECK

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QUICK ANSWERS

Electricity and Electric Circuits FAQ

Why is parallel equivalent resistance smaller than either branch?

Adding a branch provides another path for charge, so the network allows more total current at the same voltage.

Does current get used up by a resistor?

No. Charge flow is conserved; the resistor transfers electrical energy to heat, light, or another form.

Why can an extension cord overload?

It carries the sum of appliance currents, and excessive current produces strong resistive heating.

RELATED COMPETENCIES

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